SwiftyJSON

Swift 언어로 만든 개발 라이브러리 관련 프로젝트예요. 전 세계 개발자 2.3만 명이 스타(좋아요)를 눌렀어요. 깃허브에 올라온 설치파일이 없는 개발자용 프로젝트예요. 마지막 수정은 2개월 전이에요.

👩‍💻 개발자용⭐ 2.3만 개발 라이브러리

원문 소개: The better way to deal with JSON data in Swift.

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git clone https://github.com/SwiftyJSON/SwiftyJSON.git

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만든 언어Swift
최신 버전5.0.2 · 2024년 3월 27일
활동만든 날 2014.6.18 · 최근 수정 2개월 전 · 열린 이슈(질문) 140개

설명서 (README)

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SwiftyJSON

CI

Carthage compatible CocoaPods Platform Reviewed by Hound

SwiftyJSON makes it easy to deal with JSON data in Swift.

  1. Why is the typical JSON handling in Swift NOT good
  2. Requirements
  3. Integration
  4. Usage
  5. Work with Alamofire
  6. Work with Moya
  7. SwiftyJSON Model Generator

Why is the typical JSON handling in Swift NOT good?

Swift is very strict about types. But although explicit typing is good for saving us from mistakes, it becomes painful when dealing with JSON and other areas that are, by nature, implicit about types.

Take the Twitter API for example. Say we want to retrieve a user's "name" value of some tweet in Swift (according to Twitter's API).

The code would look like this:

if let statusesArray = try? JSONSerialization.jsonObject(with: data, options: .allowFragments) as? [[String: Any]],
    let user = statusesArray[0]["user"] as? [String: Any],
    let username = user["name"] as? String {
    // Finally we got the username
}

It's not good.

Even if we use optional chaining, it would be messy:

if let JSONObject = try JSONSerialization.jsonObject(with: data, options: .allowFragments) as? [[String: Any]],
    let username = (JSONObject[0]["user"] as? [String: Any])?["name"] as? String {
        // There's our username
}

An unreadable mess--for something that should really be simple!

With SwiftyJSON all you have to do is:

let json = try? JSON(data: dataFromNetworking)
if let userName = json[0]["user"]["name"].string {
  //Now you got your value
}

And don't worry about the Optional Wrapping thing. It's done for you automatically.

let json = try? JSON(data: dataFromNetworking)
let result = json[999999]["wrong_key"]["wrong_name"]
if let userName = result.string {
    //Calm down, take it easy, the ".string" property still produces the correct Optional String type with safety
} else {
    //Print the error
    print(result.error)
}

Requirements

  • iOS 8.0+ | macOS 10.10+ | tvOS 9.0+ | watchOS 2.0+
  • Xcode 16+
  • Swift 6.0+

Integration

CocoaPods (iOS 8+, OS X 10.9+)

You can use CocoaPods to install SwiftyJSON by adding it to your Podfile:

platform :ios, '8.0'
use_frameworks!

target 'MyApp' do
    pod 'SwiftyJSON', '~> 4.0'
end

Carthage (iOS 8+, OS X 10.9+)

You can use Carthage to install SwiftyJSON by adding it to your Cartfile:

github "SwiftyJSON/SwiftyJSON" ~> 4.0

If you use Carthage to build your dependencies, make sure you have added SwiftyJSON.framework to the "Linked Frameworks and Libraries" section of your target, and have included them in your Carthage framework copying build phase.

Swift Package Manager

You can use The Swift Package Manager to install SwiftyJSON by adding the proper description to your Package.swift file:

// swift-tools-version:4.0
import PackageDescription

let package = Package(
    name: "YOUR_PROJECT_NAME",
    dependencies: [
        .package(url: "https://github.com/SwiftyJSON/SwiftyJSON.git", from: "4.0.0"),
    ]
)

Then run swift build whenever you get prepared.

Manually (iOS 7+, OS X 10.9+)

To use this library in your project manually you may:

  1. for Projects, just drag SwiftyJSON.swift to the project tree
  2. for Workspaces, include the whole SwiftyJSON.xcodeproj

Usage

Initialization

import SwiftyJSON
let json = try? JSON(data: dataFromNetworking)

Or

let json = JSON(jsonObject)

Or

if let dataFromString = jsonString.data(using: .utf8, allowLossyConversion: false) {
    let json = JSON(data: dataFromString)
}

Subscript

// Getting a double from a JSON Array
let name = json[0].double
// Getting an array of string from a JSON Array
let arrayNames =  json["users"].arrayValue.map {$0["name"].stringValue}
// Getting a string from a JSON Dictionary
let name = json["name"].stringValue
// Getting a string using a path to the element
let path: [JSONSubscriptType] = [1,"list",2,"name"]
let name = json[path].string
// Just the same
let name = json[1]["list"][2]["name"].string
// Alternatively
let name = json[1,"list",2,"name"].string
// With a hard way
let name = json[].string
// With a custom way
let keys:[JSONSubscriptType] = [1,"list",2,"name"]
let name = json[keys].string

Loop

// If json is .Dictionary
for (key,subJson):(String, JSON) in json {
   // Do something you want
}

The first element is always a String, even if the JSON is an Array

// If json is .Array
// The `index` is 0..<json.count's string value
for (index,subJson):(String, JSON) in json {
    // Do something you want
}

Error

SwiftyJSON 4.x

SwiftyJSON 4.x introduces an enum type called SwiftyJSONError, which includes unsupportedType, indexOutOfBounds, elementTooDeep, wrongType, notExist and invalidJSON, at the same time, ErrorDomain are being replaced by SwiftyJSONError.errorDomain. Note: Those old error types are deprecated in SwiftyJSON 4.x and will be removed in the future release.

SwiftyJSON 3.x

Use a subscript to get/set a value in an Array or Dictionary

If the JSON is:

  • an array, the app may crash with "index out-of-bounds."
  • a dictionary, it will be assigned to nil without a reason.
  • not an array or a dictionary, the app may crash with an "unrecognised selector" exception.

This will never happen in SwiftyJSON.

let json = JSON(["name", "age"])
if let name = json[999].string {
    // Do something you want
} else {
    print(json[999].error!) // "Array[999] is out of bounds"
}
let json = JSON(["name":"Jack", "age": 25])
if let name = json["address"].string {
    // Do something you want
} else {
    print(json["address"].error!) // "Dictionary["address"] does not exist"
}
let json = JSON(12345)
if let age = json[0].string {
    // Do something you want
} else {
    print(json[0])       // "Array[0] failure, It is not an array"
    print(json[0].error!) // "Array[0] failure, It is not an array"
}

if let name = json["name"].string {
    // Do something you want
} else {
    print(json["name"])       // "Dictionary[\"name"] failure, It is not an dictionary"
    print(json["name"].error!) // "Dictionary[\"name"] failure, It is not an dictionary"
}

Optional getter

// NSNumber
if let id = json["user"]["favourites_count"].number {
   // Do something you want
} else {
   // Print the error
   print(json["user"]["favourites_count"].error!)
}
// String
if let id = json["user"]["name"].string {
   // Do something you want
} else {
   // Print the error
   print(json["user"]["name"].error!)
}
// Bool
if let id = json["user"]["is_translator"].bool {
   // Do something you want
} else {
   // Print the error
   print(json["user"]["is_translator"].error!)
}
// Int
if let id = json["user"]["id"].int {
   // Do something you want
} else {
   // Print the error
   print(json["user"]["id"].error!)
}
...

Non-optional getter

Non-optional getter is named xxxValue

// If not a Number or nil, return 0
let id: Int = json["id"].intValue
// If not a String or nil, return ""
let name: String = json["name"].stringValue
// If not an Array or nil, return []
let list: Array<JSON> = json["list"].arrayValue
// If not a Dictionary or nil, return [:]
let user: Dictionary<String, JSON> = json["user"].dictionaryValue

Setter

json["name"] = JSON("new-name")
json[0] = JSON(1)
json["id"].int =  1234567890
json["coordinate"].double =  8766.766
json["name"].string =  "Jack"
json.arrayObject = [1,2,3,4]
json.dictionaryObject = ["name":"Jack", "age":25]

Raw object

let rawObject: Any = json.object
let rawValue: Any = json.rawValue
//convert the JSON to raw NSData
do {
	let rawData = try json.rawData()
  //Do something you want
} catch {
	print("Error \(error)")
}
//convert the JSON to a raw String
if let rawString = json.rawString() {
  //Do something you want
} else {
	print("json.rawString is nil")
}

Existence

// shows you whether value specified in JSON or not
if json["name"].exists()

Literal convertibles

For more info about literal convertibles: Swift Literal Convertibles

// StringLiteralConvertible
let json: JSON = "I'm a json"
// IntegerLiteralConvertible
let json: JSON =  12345
// BooleanLiteralConvertible
let json: JSON =  true
// FloatLiteralConvertible
let json: JSON =  2.8765
// DictionaryLiteralConvertible
let json: JSON =  ["I":"am", "a":"json"]
// ArrayLiteralConvertible
let json: JSON =  ["I", "am", "a", "json"]
// With subscript in array
var json: JSON =  [1,2,3]
json[0] = 100
json[1] = 200
json[2] = 300
json[999] = 300 // Don't worry, nothing will happen
// With subscript in dictionary
var json: JSON =  ["name": "Jack", "age": 25]
json["name"] = "Mike"
json["age"] = "25" // It's OK to set String
json["address"] = "L.A." // Add the "address": "L.A." in json
// Array & Dictionary
var json: JSON =  ["name": "Jack", "age": 25, "list": ["a", "b", "c", ["what": "this"]]]
json["list"][3]["what"] = "that"
json["list",3,"what"] = "that"
let path: [JSONSubscriptType] = ["list",3,"what"]
json[path] = "that"
// With other JSON objects
let user: JSON = ["username" : "Steve", "password": "supersecurepassword"]
let auth: JSON = [
  "user": user.object, // use user.object instead of just user
  "apikey": "supersecretapitoken"
]

Merging

It is possible to merge one JSON into another JSON. Merging a JSON into another JSON adds all non existing values to the original JSON which are only present in the other JSON.

If both JSONs contain a value for the same key, mostly this value gets overwritten in the original JSON, but there are two cases where it provides some special treatment:

  • In case of both values being a JSON.Type.array the values form the array found in the other JSON getting appended to the original JSON's array value.
  • In case of both values being a JSON.Type.dictionary both JSON-values are getting merged the same way the encapsulating JSON is merged.

In a case where two fields in a JSON have different types, the value will get always overwritten.

There are two different fashions for merging: merge modifies the original JSON, whereas merged works non-destructively on a copy.

let original: JSON = [
    "first_name": "John",
    "age": 20,
    "skills": ["Coding", "Reading"],
    "address": [
        "street": "Front St",
        "zip": "12345",
    ]
]

let update: JSON = [
    "last_name": "Doe",
    "age": 21,
    "skills": ["Writing"],
    "address": [
        "zip": "12342",
        "city": "New York City"
    ]
]

let updated = original.merge(with: update)
// [
//     "first_name": "John",
//     "last_name": "Doe",
//     "age": 21,
//     "skills": ["Coding", "Reading", "Writing"],
//     "address": [
//         "street": "Front St",
//         "zip": "12342",
//         "city": "New York City"
//     ]
// ]

Removing elements

If you are storing dictionaries, you can remove elements using dictionaryObject.removeValue(forKey:). This mutates the JSON object in place.

For example:

var object = JSON([
    "one": ["color": "blue"],
    "two": ["city": "tokyo",
            "country": "japan",
            "foods": [
                "breakfast": "tea",
                "lunch": "sushi"
                ]
            ]
])

Lets remove the country key:

object["two"].dictionaryObject?.removeValue(forKey: "country")

If you print(object), you'll see that the country key no longer exists.

{
  "one" : {
    "color" : "blue"
  },
  "two" : {
    "city" : "tokyo",
    "foods" : {
      "breakfast" : "tea",
      "lunch" : "sushi"
    }
  }
}

This also works for nested dictionaries:

object["two"]["foods"].dictionaryObject?.removeValue(forKey: "breakfast")
{
  "one" : {
    "color" : "blue"
  },
  "two" : {
    "city" : "tokyo",
    "foods" : {
      "lunch" : "sushi"
    }
  }
}

String representation

There are two options available:

  • use the default Swift one
  • use a custom one that will handle optionals well and represent nil as "null":
let dict = ["1":2, "2":"two", "3": nil] as [String: Any?]
let json = JSON(dict)
let representation = json.rawString(options: [.castNilToNSNull: true])
// representation is "{\"1\":2,\"2\":\"two\",\"3\":null}", which represents {"1":2,"2":"two","3":null}

Work with Alamofire

SwiftyJSON nicely wraps the result of the Alamofire JSON response handler:

Alamofire.request(url, method: .get).validate().responseJSON { response in
    switch response.result {
    case .success(let value):
        let json = JSON(value)
        print("JSON: \(json)")
    case .failure(let error):
        print(error)
    }
}

We also provide an extension of Alamofire for serializing NSData to SwiftyJSON's JSON.

See: Alamofire-SwiftyJSON

Work with Moya

SwiftyJSON parse data to JSON:

let provider = MoyaProvider<Backend>()
provider.request(.showProducts) { result in
    switch result {
    case let .success(moyaResponse):
        let data = moyaResponse.data
        let json = JSON(data: data) // convert network data to json
        print(json)
    case let .failure(error):
        print("error: \(error)")
    }
}

SwiftyJSON Model Generator

Tools to generate SwiftyJSON Models

자주 묻는 질문

SwiftyJSON 무료로 쓸 수 있나요?

네, MIT 라이선스로 공개된 오픈소스예요. 무료이고 회사·상업용으로 써도 돼요. 출처(저작권 표시)만 남기면 돼요. 깃허브 저장소에서 누구나 내려받을 수 있어요.

SwiftyJSON 설치는 어떻게 하나요?

따로 설치파일이 없어서 README 설명서의 안내를 따라 설치해야 해요. ZIP 다운로드로 전체 코드를 받거나, 브라우저에서 바로 열어 코드를 둘러볼 수 있어요.

코딩을 몰라도 SwiftyJSON 쓸 수 있나요?

조금 어려울 수 있어요. 완성된 설치파일이 없는 개발자용 프로젝트라서 터미널 명령어나 개발 환경이 필요해요. 처음이라면 Codespaces로 브라우저에서 먼저 실행해 보세요.

SwiftyJSON 인기는 어느 정도인가요?

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